Light of wavelength 550 nm falls normally on a slit of width 22.0 × 10 - 5 cm . The angular position of the second minima from the central maximum will be (in radians):

Step-by-step solution

a sin θ = 2 λ ,     2 n d   dark ⇒ sin θ = 2 λ a = 2 × 550 × 10 − 9 22 × 10 − 7 ⇒ θ ≃ π 6   rad