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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Physics
Chapter
Wave Optics

JEE Main 2018 · 15 April · Physics · Wave Optics

Light of wavelength 550nm falls normally on a slit of width 22.0 ×...

Light of wavelength 550nm550nm falls normally on a slit of width 22.0×10−5cm22.0 \times {10}^{- 5}cm. The angular position of the second minima from the central maximum will be (in radians):

Options

  1. Aπ4\dfrac{\pi}{4}
  2. Bπ8\dfrac{\pi}{8}
  3. Cπ12\dfrac{\pi}{12}
  4. Dπ6\dfrac{\pi}{6}

Correct answer

D. π6\dfrac{\pi}{6}

Step-by-step solution

asinθ=2λ,2nddarkasin\theta = 2\lambda, {2}^{nd}\text{dark}

⇒sinθ=2λa=2×550×10−922×10−7⇒ sin\theta = \dfrac{2\lambda}{a} = \dfrac{2 \times 550 \times {10}^{- 9}}{22 \times {10}^{- 7}}⇒θ≃π6rad⇒ \theta ≃ \dfrac{\pi}{6}rad

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