A single slit of width b is illuminated by a coherent monochromatic light of wavelength λ . If the second and fourth minima in the diffraction pattern at a distance 1cm from the slit are at 3cm and 6cm respectively from

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Correct answer: D. 3 . 0cm

For secondary minima dsin θ = nλ sin θ = (nλ)/(d) For second minima n = 2 sin θ = (2λ)/(d) = tan θ _ 1 = x _ 1 D For fourth minima n = 4 sin θ _ 2 = (4λ)/(d) = x _ 2 D Distance between both minima is x _ 2 - x _ 1 = (4λ)/(d) - (2λ)/(d) = (2λ)/(d) = 6 - 3 =3cm Width of central maxima, = (2λ)/(d) = 3cm

A single slit of width b is illuminated by a coherent monochromatic...

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