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In Young's double slit interference experiment, the slit widths are in the ratio 1: 25 . Then the ratio of intensity at the maxima and minima in the interference pattern is

Options

  1. A3: 2
  2. B1: 25
  3. C9: 4
  4. D1: 5

Correct answer

C. 9: 4

Step-by-step solution

We know that, I_ I_ = ( ₁ ₂ +1 )^2 ( ₁ ₂ -1 )^2 I_ and I_ are maximum and minimum intensity ₁ and ₂ are widths of two slits I_ I_ = ( 1 25 +1 )^2 ( 1 25 -1 )^2 ( ₁ ₂ = 1 25 given ) On solving we get, I_ I_ = 36 25 16 25 = 9 4 =9: 4

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