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The maximum number of possible interference maxima for slit separation equal to 1.8 , where is the wavelength of light used, in a Young's double slit experiment is

Options

  1. Azero
  2. B3
  3. Cinfinite
  4. D5

Correct answer

B. 3

Step-by-step solution

As = n d and cannot be 1 1= n 1.8 or n=1.8 Hence maximum number of possible interference maximas, 0, 1 i.e. 3

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