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JEE Main 2002
Exam
JEE Main
Year
2002
Subject
Physics
Chapter
Wave Optics

JEE Main 2002 · Physics · Wave Optics

Wavelength of light used in an optical instrument are λ_1=4000 Å...

Wavelength of light used in an optical instrument are λ1=4000A˚\lambda_1=4000 Å and λ2=5000A˚\lambda_2=5000 Å, then ratio of their respective resolving powers (corresponding to λ1\lambda_1 and λ2\lambda_2 ) is

Options

  1. A16 : 25
  2. B9 : 1
  3. C4 : 5
  4. D5 : 4

Correct answer

D. 5 : 4

Step-by-step solution

Resolving power α(1/λ)\alpha(1 / \lambda). Hence, ( R.P )1( R.P )2=λ2λ1=54\frac{(\text{ R.P })_1}{(\text{ R.P })_2}=\frac{\lambda_2}{\lambda_1}=\frac{5}{4}
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