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JEE Main 20258 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2025 · 8 April · Evening Shift · Physics · Waves and Sound

Two strings with circular cross section and made of same material,...

Two strings with circular cross section and made of same material, are stretched to have same amount of tension. A transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section R is v1\mathrm{v}_1, and that in the other string having radius of cross section R/2R / 2 is v2v_2. Then v2v1=\frac{v_2}{v_1}=

Options

  1. A2\sqrt{2}
  2. B2
  3. C8
  4. D4

Correct answer

B. 2

Step-by-step solution

v=Tμ=TfπR2v2v1=R1R2=2\begin{aligned} & v=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{T}{f \pi R^2}} \\ & \frac{v_2}{v_1}=\frac{R_1}{R_2}=2\end{aligned}
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