A tuning fork resonates with a sonometer wire of length 1m stretched with a tension of 6N . When the tension in the wire is changed to 54N, the same tuning fork produces 12 beats per second with it. The frequency of the

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Frequency of sonometer wire is given by, $f = \dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

Therefore, ${f}_{1} = \dfrac{1}{2}\sqrt{\dfrac{6}{\mu}}$ ${f}_{2} = \dfrac{1}{2}\sqrt{\dfrac{54}{\mu}}$

Hence, $\dfrac{{f}_{1}}{{f}_{2}} = \dfrac{1}{3}$

Also it is given that, ${f}_{2} - {f}_{1} = 12$

So, ${f}_{1} = 6Hz$ .

A tuning fork resonates with a sonometer wire of length 1m...

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