JEE Main202430 Jan 2024Morning ShiftPhysicsWaves and SoundActual
In a closed organ pipe, the frequency of fundamental note is 30 Hz . A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110 Hz . If the organ pipe has a cross-sectional area of 2 cm 2 , the amount of water poured in the organ tube is ________ g . (Take speed of sound in air is 330 m s - 1 )
Correct answer
0
Step-by-step solution
Fundamental frequency for closed organ pipe in the first part: V 4 l 1 = 30 ⇒ l 1 = 11 4 m Similarly, for second part: V 4 l 2 = 110 ⇒ l 2 = 3 4 m Therefore, change in length Δ l = 2 m Change in volume = AΔ l = 400 cm 3 M = 400 g ; ∵ ρ = 1 g cm - 3