JEE Main202312 Apr 2023Morning ShiftPhysicsWaves and SoundActual
For a certain organ pipe, the first three resonance frequencies are in the ratio of 1 : 3 : 5 respectively. If the frequency of fifth harmonic is 405 Hz and the speed of sound in air is 324 m s – 1 the length of the organ pipe is _____ m .
Correct answer
0
Step-by-step solution
It is given, f 5 = 405   Hz . As the first three resonance frequencies are in the ratio of 1 : 3 : 5 , therefore it must be a closed organ pipe. The frequency formula in a closed organ pipe is given by f = n v 4 l . So, 5 v 4 I = 405   Hz ⇒ I = 405 × 4 5 × 324 = 1   m