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JEE Main 202311 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2023 · 11 April · Morning Shift · Physics · Waves and Sound

The equation of wave is given by Y = 10 ^ - 2 2π(160t - 0 . 5x +...

The equation of wave is given by Y=10−2sin⁡2π(160t−0.5x+π4)Y = {10}^{- 2}\sin 2\pi\left(160t - 0 . 5x + \dfrac{\pi}{4}\right), where xx and YY are in mm and tt in ss. The speed of the wave is _______ kmh−1km{h}^{- 1}.

Correct answer

0

Step-by-step solution

The equation of the wave is

Y=10−2sin⁡2π(160t−0.5x+π4)Y = {10}^{- 2}\sin 2\pi ( 160t - 0 . 5x + \dfrac{\pi}{4} )

The velocity of a wave is given by v=ωk...(i)v = \dfrac{\omega}{k} . . . ( i ).

A wave equation is given by

Y=Asin(\omegat−kx+ϕ)Y = Asin\left(\omegat - kx + ϕ\right)

Using equation (i),

v=(2π×1602π×0.5)=320ms−1v = \left(\dfrac{2\pi \times 160}{2\pi \times 0 .5}\right) = 320m{s}^{- 1}

⇒v=320×185⇒ v = 320 \times \dfrac{18}{5}

⇒v=1152kmh−1⇒ v = 1152km{h}^{- 1}

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