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JEE Main 202229 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
29 July
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2022 · 29 July · Evening Shift · Physics · Waves and Sound

The speed of a transverse wave passing through a string of length...

The speed of a transverse wave passing through a string of length 50cm50cm and mass 10g10g is 60ms−160m{s}^{- 1}. The area of cross-section of the wire is 2.0mm22 . 0{mm}^{2} and its Young's modulus is 1.2×1011Nm−21 . 2 \times {10}^{11}N{m}^{- 2}. The extension of the wire over its natural length due to its tension will be x×10−5mx \times {10}^{- 5}m. The value of xx is _____ .

Correct answer

0

Step-by-step solution

The wave speed in string is given by vw=Tμ{v}_{w} = \sqrt{\dfrac{T}{\mu}}, where, TT is tension and μ=ml\mu = \dfrac{m}{l} is linear mass density.

Putting the values, we have

⇒60=T10×10−3×0.5⇒ 60 = \sqrt{\dfrac{T}{10 \times {10}^{- 3}} \times 0 . 5}

⇒T=(60)2×10−20.5=72N⇒ T = \dfrac{{\left(60\right)}^{2} \times {10}^{- 2}}{0 . 5} = 72N

The Young's modulus is given by Y=FlA∆lY = \dfrac{Fl}{A ∆ l}, here, AA is area.

From above the extension of the wire is \Deltal=TlAY=72×0.52×10−6×1.2×1011\Deltal = \dfrac{Tl}{AY} = \dfrac{72 \times 0 . 5}{2 \times {10}^{- 6} \times 1 . 2 \times {10}^{11}}=72×524×10−5=15×10−5m= \dfrac{72 \times 5}{24} \times {10}^{- 5} = 15 \times {10}^{- 5}m.

Hence, the value of x=15x = 15.

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