A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is _____ Hz .

Step-by-step solution

Each fork produces 4 beats per second with the previous means each fork has frequency 4   Hz more than the previous. Using relation, f last = f first + N - 1 x , here, N is the number of tuning fork in series and x is beat frequency between two successive forks. 2 f 0 = f 0 +   20 - 1 4 ⇒ 2 f 0 = f 0 + 76 ⇒ f 0 = 76   Hz Frequency of last tuning fork is 152   Hz .