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JEE Main 202127 AugustEvening Shift

Exam: JEE Main
Year: 2021
Date: 27 August
Shift: Evening Shift
Subject: Physics
Chapter: Waves and Sound

JEE Main 2021 · 27 August · Evening Shift · Physics · Waves and Sound

A tuning fork is vibrating at 250Hz . The length of the shortest...

A tuning fork is vibrating at

250Hz

. The length of the shortest closed organ pipe that will resonate with the tuning fork will be _____

cm

. (Take speed of sound in air as

340{ms}^{- 1}

)

Correct answer

0

Step-by-step solution

For closed organ pipe

$f = ( 2n + 1 ) \dfrac{v}{4l}$

for minimum length, $n = 0$

${f}_{0} = \dfrac{v}{4l}$

$⇒ l = \dfrac{v}{4{f}_{0}}$

$= \dfrac{340}{4 \times 250} = 34cm$

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