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JEE Main 20204 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
4 September
Shift
Morning Shift
Subject
Physics
Chapter
Waves and Sound

JEE Main 2020 · 4 September · Morning Shift · Physics · Waves and Sound

For a transvers wave travelling, along a straight line, the...

For a transvers wave travelling, along a straight line, the distance between two peaks (crests) is 5m5\text{m}, while the distance between one crest and one trough is 1.5m1 . 5\text{m}. The possible wavelengths (in m\text{m}) of the waves are:

Options

  1. A1,3,51, 3, 5
  2. B11,13,15,.....\dfrac{1}{1}, \dfrac{1}{3}, \dfrac{1}{5}, . . . . .
  3. C1,2,3,....1, 2, 3, . . . .
  4. D12,14,16,.....\dfrac{1}{2}, \dfrac{1}{4}, \dfrac{1}{6}, . . . . .

Correct answer

B. 11,13,15,.....\dfrac{1}{1}, \dfrac{1}{3}, \dfrac{1}{5}, . . . . .

Step-by-step solution

Trough to crest distance

1.5=(2n1+1)λ21 .5 = \left(2{n}_{1} + 1\right)\dfrac{\lambda}{2} ......(1)( 1 )

Trough to trough distance

5=(n2λ)5 = \left({n}_{2}\lambda\right) .....(2)( 2 )

from (1)( 1 ) and (2)( 2 )

1.55=2n1+12(n2)\dfrac{1 .5}{5} = \dfrac{2{n}_{1} + 1}{2\left({n}_{2}\right)}

3n2=10n1+53{n}_{2} = 10{n}_{1} + 5

n1{n}_{1} and n2{n}_{2} are integer

(1)( 1 ) n1=1,n2=5,λ=1{n}_{1} = 1, {n}_{2} = 5, \lambda = 1

(2)( 2 ) n1=4,n2=15,λ=1/3{n}_{1} = 4, {n}_{2} = 15, \lambda = 1 / 3

(3)( 3 ) n1=7,n2=25,λ=1/5{n}_{1} = 7, {n}_{2} = 25, \lambda = 1 / 5

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