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A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8 .0 N . The string is set into vibration using an external vibrator of frequency 100 Hz . The separation between successive nodes on the string is close to

Options

  1. A20 . 0   cm
  2. B10 . 0   cm
  3. C16 .6   cm
  4. D33 . 3   cm

Correct answer

A. 20 . 0   cm

Step-by-step solution

V = f λ T μ = f λ 8 5 × 10 - 3 = 100 λ λ = 40   cm λ 2 = 20   cm

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