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JEE Main 201816 AprilOnline

Exam: JEE Main
Year: 2018
Date: 16 April
Mode: Online
Subject: Physics
Chapter: Waves and Sound

JEE Main 2018 · 16 April · Online · Physics · Waves and Sound

The end correction of a resonance column is 1cm . If the shortest...

The end correction of a resonance column is

1cm

. If the shortest length resonating with the tuning fork is

10cm

, the next resonating length should be

Options

A $32cm$
B $40cm$
C $28cm$
D $36cm$

Correct answer

A. $32cm$

Step-by-step solution

Given:

e = 1cm

. For first resonance,

\dfrac{\lambda}{4} = {l}_{1} + e = 11cm

. For second resonance,

\dfrac{3\lambda}{4} = {l}_{2} + e ⇒ {l}_{2} = 3 \times 11 - 1 = 32cm

.

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