JEE Main2018PhysicsWaves and SoundActual
A granite rod of 60 cm length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is 2.7 × 10 3 kg m - 3 and its Young's modulus is 9.27 × 10 10 Pa . What will be the fundamental frequency of the longitudinal vibrations?
Options
- A7 . 5   kHz
- B5   kHz
- C2 . 5   kHz
- D10   kHz
Correct answer
B. 5   kHz
Step-by-step solution
L = ⋋ 2 ⇒ ⋋ = 2 L = 1.2   m v = y ρ = 5.86 × 10 3   m   s - 1 ∴   Fundamental   frequency = v ⋋ = 4.88   kHz ≈ 5   kHz