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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Physics
Chapter
Waves and Sound

JEE Main 2018 · 8 April · Physics · Waves and Sound

A granite rod of 60cm length is clamped at its middle point and is...

A granite rod of 60cm60cm length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is 2.7×103kgm−32.7 \times {10}^{3}kg{m}^{- 3} and its Young's modulus is 9.27×1010Pa9.27 \times {10}^{10}Pa. What will be the fundamental frequency of the longitudinal vibrations?A granite rod of 60cm length is clamped at its middle point and is set into longitudinal vibrations. The density of

Options

  1. A7.5kHz7 . 5kHz
  2. B5kHz5kHz
  3. C2.5kHz2 . 5kHz
  4. D10kHz10kHz

Correct answer

B. 5kHz5kHz

Step-by-step solution

A granite rod of 60cm length is clamped at its middle point and is set into longitudinal vibrations. The density of

L=⋋2⇒⋋=2L=1.2mL = \dfrac{⋋}{2} ⇒ ⋋ = 2L = 1.2m

v=yρ=5.86×103ms−1v = \sqrt{\dfrac{y}{ρ}} = 5.86 \times {10}^{3}m{s}^{- 1}

∴Fundamentalfrequency=v⋋=4.88kHz∴ Fundamental frequency = \dfrac{v}{⋋} = 4.88kHz

≈5kHz\approx 5kHz
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