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JEE Main 20149 AprilOnline
Exam
JEE Main
Year
2014
Date
9 April
Mode
Online
Subject
Physics
Chapter
Waves and Sound

JEE Main 2014 · 9 April · Online · Physics · Waves and Sound

A transverse wave is represented by : y = (1 0)/(π) ( 2 π T t - (2...

A transverse wave is represented by : y=10πsin⁡(2πTt−2πλx)\text{y} = \dfrac{1 0}{\pi} \sin \left(\dfrac{2 \pi}{\text{T}} \text{t} - \dfrac{2 \pi}{\lambda} \text{x}\right) For what value of the wavelength the wave velocity is twice the maximum particle velocity?

Options

  1. A40 cm
  2. B60 cm
  3. C10 cm
  4. D20 cm

Correct answer

A. 40 cm

Step-by-step solution

wavevelocity=nλwavevelocity = n\lambda

{( {V}_{p} )}_\max = a\omega

nλ=2a(2\pin)n \lambda = 2a\left(2\pin\right)

λ=2(a)2π\lambda = 2 ( a ) 2\pi

=2.10π.2π= 2 . \dfrac{10}{\pi} . 2\pi

= 40 cm
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