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JEE Main 201322 AprilOnline
Exam
JEE Main
Year
2013
Date
22 April
Mode
Online
Subject
Physics
Chapter
Waves and Sound

JEE Main 2013 · 22 April · Online · Physics · Waves and Sound

A and B are two sources generating sound waves. A listener is...

A and B are two sources generating sound waves. A listener is situated at C\mathrm{C}. The frequency of the source at A\mathrm{A} is 500 Hz500 \mathrm{~Hz}. A, now, moves towards C\mathrm{C} with a speed 4 m/s4 \mathrm{~m} / \mathrm{s}. The number of beats heard at C\mathrm{C} is 6 . When A\mathrm{A} moves away from CC with speed 4 m/s4 \mathrm{~m} / \mathrm{s}, the number of beats heard at C\mathrm{C} is 18 . The speed of sound is 340 m/s340 \mathrm{~m} / \mathrm{s}. The frequency of the source at B\mathrm{B} is : A and B are two sources generating sound waves. A listener is situated at C . The frequency of the source at A is 500

Options

  1. A500 Hz500 \mathrm{~Hz}
  2. B506 Hz506 \mathrm{~Hz}
  3. C512 Hz512 \mathrm{~Hz}
  4. D494 Hz494 \mathrm{~Hz}

Correct answer

C. 512 Hz512 \mathrm{~Hz}

Step-by-step solution

f=500Hz\mathrm{f}=500 \mathrm{ Hz} A and B are two sources generating sound waves. A listener is situated at C . The frequency of the source at A is 500
Case 1: When source is moving towards stationary listener apparent frequency η′=η(vv−vs)=500(340336)=506HzCase2:Whensourceismovingawayfromthestationarylistenerη′′=η(vv+vs)=500(340344)=494HzIncase1numberofbeatsheardis6andincase2numberofbeatsheardis18thereforefrequencyofthesourceatB=512Hz\eta^{\prime}=\eta \left(\frac{\mathrm{v}}{\mathrm{v}-\mathrm{v}_{\mathrm{s}}}\right) =500\left(\frac{340}{336}\right)=506 \mathrm{ Hz} Case 2 : When source is moving away from the stationary listener \eta^{\prime \prime}=\eta\left(\frac{\mathrm{v}}{\mathrm{v}+\mathrm{v}_{\mathrm{s}}}\right)=500\left(\frac{340}{344}\right)=494 \mathrm{ Hz} In case 1 number of beats heard is 6 and in case 2 number of beats heard is 18 therefore frequency of the source at \mathrm{B}=512 \mathrm{ Hz}
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