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JEE Main 2010
Exam
JEE Main
Year
2010
Subject
Physics
Chapter
Waves and Sound

JEE Main 2010 · Physics · Waves and Sound

The equation of a wave on a string of linear mass density 0.04 ~kg...

The equation of a wave on a string of linear mass density 0.04 kg m−10.04 \mathrm{~kg} \mathrm{~m}^{-1} is given by y=0.02( m)sin⁡[2π(t0.04( s)−x0.50( m))]y=0.02(\mathrm{~m}) \sin \left[2 \pi\left(\frac{\mathrm{t}}{0.04(\mathrm{~s})}-\frac{\mathrm{x}}{0.50(\mathrm{~m})}\right)\right]. The tension in the string is

Options

  1. A4.0 N4.0 \mathrm{~N}
  2. B12.5 N12.5 \mathrm{~N}
  3. C0.5 N0.5 \mathrm{~N}
  4. D6.25 N6.25 \mathrm{~N}

Correct answer

D. 6.25 N6.25 \mathrm{~N}

Step-by-step solution

T=μv2=μω2k2=0.04(2π/0.004)2(2π/0.50)2=6.25 N\mathrm{T}=\mu \mathrm{v}^2=\mu \frac{\omega^2}{\mathrm{k}^2}=0.04 \frac{(2 \pi / 0.004)^2}{(2 \pi / 0.50)^2}=6.25 \mathrm{~N}
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