If half-life of a substance is 36 minutes. Find amount left after 2 hrs . Initial amount is 10 gm ?

Step-by-step solution

Given, t _ 1 / 2 =36 ~min , t =2 hrs =120 ~min ,[ Ao ]= For first order reaction, R = 0.693 t _ 1 / 2 aligned k & = 0.693 36 =0.01925 t & = 2303 k [ A ₀ ] [ A ] aligned where, [ A ₀ ]= initial amount aligned & [ A ]= final amount & 120= 2303 0.01925 10 [ ~A ] & 10- [ A ]=1 & 1- [ A ]=1 & [ A ]=0 & [ ~A ] =1 gm aligned