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JIPMER 2012
Exam
JIPMER
Year
2012
Subject
Chemistry
Chapter
s Block Elements

JIPMER 2012 · Chemistry · s Block Elements

The correct order of decreasing first ionisation energy is

The correct order of decreasing first ionisation energy is

Options

  1. AC>B>Be>Li\mathrm{C}\gt\mathrm{B}\gt\mathrm{Be}\gt\mathrm{Li}
  2. BC>Be>B>Li\mathrm{C}\gt\mathrm{Be}\gt\mathrm{B}\gt\mathrm{Li}
  3. CB>C>Be>Li\mathrm{B}\gt\mathrm{C}\gt\mathrm{Be}\gt\mathrm{Li}
  4. DBe>Li>B>C\mathrm{Be}\gt\mathrm{Li}\gt\mathrm{B}\gt\mathrm{C}

Correct answer

B. C>Be>B>Li\mathrm{C}\gt\mathrm{Be}\gt\mathrm{B}\gt\mathrm{Li}

Step-by-step solution

On moving from left to right in a period, as the size decreases, ionisation energy increases. But first IE of elements of II A group is higher than that of the elements of III A group because of the stable ns2n s^2 configuration (of II A group). Hence, the order of first ionisation energy is (C>Be>B>LiGroup no. (IV)  (II)  (III)  (I) \begin{array}{c} & \mathrm{C} & > & \mathrm{Be} & > & \mathrm{B} & > & \mathrm{Li} \\ \text{Group no.} & \text{ (IV) } & & \text{ (II) } & & \text{ (III) } & & \text{ (I) } \end{array})
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