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JIPMER 2019
Exam
JIPMER
Year
2019
Subject
Chemistry
Chapter
Structure of Atom

JIPMER 2019 · Chemistry · Structure of Atom

^ 19 F^ -1 ,~ ^ 16 O^ -2 ,~ ^ 20 Ne choose the correct statement

19F−1, 16O−2, 20Ne{ }^{19} \mathrm{F}^{-1},~{ }^{16} \mathrm{O}^{-2},~{ }^{20} \mathrm{Ne} choose the correct statement

Options

  1. ABoth O−2\mathrm{O}^{-2} and F−\mathrm{F}^{-}are isoelectronic
  2. BAll given have equal no of e−e^{-}
  3. CF−\mathrm{F}^{-}and Ne have equal number of e−\mathrm{e}^{-}
  4. DAll of the above

Correct answer

D. All of the above

Step-by-step solution

The total number of electrons in the given species are as follows. 919 F−1=9+1=10816O−2=8+2=10;1020Ne=10\begin{aligned} & { }_9^{19} \mathrm{~F}^{-1}=9+1=10 \\ & { }_8^{16} \mathrm{O}^{-2}=8+2=10 ;{ }_{10}^{20} \mathrm{Ne}=10 \end{aligned} Thus, all the given statements are correct.
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