The Vividh Bharti Station of All India Radio, Delhi, broadcasts on a frequency of 1,368 kHz (Kilohertz). Calculate the wavelength (λ) of the electromagnetic radiation emitted by transmitter. Which part of the

Correct answer: D. 219.3 m and radiowave v=1,368 × 10^3 ~Hz λ=(C)/(v)= 3 × 10^8 ~m / s 1368 × 10^3 ~s^ -1 =219.3 ~m The range of wavelength of radiowaves is 100 m to radiation is 10000 m .

JIPMER 2015

Exam: JIPMER
Year: 2015
Subject: Chemistry
Chapter: Structure of Atom

JIPMER 2015 · Chemistry · Structure of Atom

The Vividh Bharti Station of All India Radio, Delhi, broadcasts on...

The Vividh Bharti Station of All India Radio, Delhi, broadcasts on a frequency of

1,368 \mathrm{kHz}

(Kilohertz). Calculate the wavelength

(\lambda)

of the electromagnetic radiation emitted by transmitter. Which part of the electromagnetic spectrum does it belong to?

Options

A319.4 m and X-rays
B319.4 m and radiowave
C219.3 m and microwave
D219.3 m and radiowave

Correct answer

D. 219.3 m and radiowave

Step-by-step solution

v=1,368 \times 10^3 \mathrm{~Hz}

\lambda=\frac{C}{v}=\frac{3 \times 10^8 \mathrm{~m} / \mathrm{s}}{1368 \times 10^3 \mathrm{~s}^{-1}}=219.3 \mathrm{~m}

The range of wavelength of radiowaves is 100 m to radiation is 10000 m .

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