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JIPMER 2011
Exam
JIPMER
Year
2011
Subject
Chemistry
Chapter
Structure of Atom

JIPMER 2011 · Chemistry · Structure of Atom

A 600 W mercury lamp emits monochromatic radiation of wavelength...

A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm . How many photons are emitted from the lamp per second? (h=6.626×10−34 J−s;velocity\left(h=6.626 \times 10^{-34} \mathrm{~J}-\mathrm{s}\right.; velocity of light =3×108 ms−1)\left.=3 \times 10^8 \mathrm{~ms}^{-1}\right)

Options

  1. A1×10191 \times 10^{19}
  2. B1×10201 \times 10^{20}
  3. C1×10211 \times 10^{21}
  4. D1×10231 \times 10^{23}

Correct answer

C. 1×10211 \times 10^{21}

Step-by-step solution

Given, power =600 Wλ=331.3 nm=331.3×10−9 m=600 \mathrm{~W}\lambda=331.3 \mathrm{~nm}=331.3 \times 10^{-9} \mathrm{~m} Power = energy  time =nhvt=nhcλt=\frac{\text{ energy }}{\text{ time }} =\frac{n h v}{t}=\frac{n h c}{\lambda t} or n= power ×λthc=600×331.3×10−9×16.626×10−34×3×108n=1×1021\quad n=\frac{\text{ power } \times \lambda t}{h c} =\frac{600 \times 331.3 \times 10^{-9} \times 1}{6.626 \times 10^{-34} \times 3 \times 10^8} n=1 \times 10^{21}
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