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JIPMER 2009
Exam
JIPMER
Year
2009
Subject
Chemistry
Chapter
Structure of Atom

JIPMER 2009 · Chemistry · Structure of Atom

What is the wavelength (in m ) of a particle of mass 6.62 × 10^ -29...

What is the wavelength (in m ) of a particle of mass 6.62×10−29 g6.62 \times 10^{-29} \mathrm{~g} moving with a velocity of 103 ms−110^3 \mathrm{~ms}^{-1} ?

Options

  1. A6.62×10−46.62 \times 10^{-4}
  2. B6.62×10−36.62 \times 10^{-3}
  3. C10−510^{-5}
  4. D10510^5

Correct answer

C. 10−510^{-5}

Step-by-step solution

According to de-Broglie equation λ=hmv=6.62×10−346.62×10−29×10−3×103=10−5 m\begin{aligned} \lambda & =\frac{h}{m v} \\ & =\frac{6.62 \times 10^{-34}}{6.62 \times 10^{-29} \times 10^{-3} \times 10^3} \\ & =10^{-5} \mathrm{~m} \end{aligned}
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