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JIPMER 2019

Exam: JIPMER
Year: 2019
Subject: Physics
Chapter: Center of Mass, Momentum and Collision

JIPMER 2019 · Physics · Center of Mass, Momentum and Collision

Two objects of mass m each moving with speed u~m / s collide at 90^...

Two objects of mass

m

each moving with speed

\mathrm{u~m} / \mathrm{s}

collide at

90^{\circ}

, then final momentum is (assume collision is inelastic)

Options

A $m u$
B $2 m u$
C $\sqrt{2} m u$
D $2 \sqrt{2} \mathrm{mu}$

Correct answer

C. $\sqrt{2} m u$

Step-by-step solution

Speed of objects

=4 \mathrm{~m} / \mathrm{s}

Since, both objects collide with

90^{\circ}

. Hence, by the law of conservation of momentum, Total moment before collision = total momentum after collision

\begin{aligned} \mid \mathrm{muî}+\mathrm{mu \hat {j } |} & =\mathrm{P}_{\mathrm{f}} \\ \sqrt{\mathrm{m}^2 \mathrm{u}^2+\mathrm{m}^2 \mathrm{u}^2} & =\mathrm{P}_{\mathrm{f}} \\ \Rightarrow \quad \mathrm{P}_{\mathrm{f}} & =\sqrt{2} \mathrm{mu} \end{aligned}

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