JIPMER2016PhysicsElectromagnetic Waves
A beam of light travelling along X -axis is described by the electric field E_Y=600 V m . (t- x c ) , the maximum magnetic force on a charge q=2 e , moving along Y -axis with the speed of 3 10^8 ~m / s is
Options
- A19.2 10⁻¹⁷ ~N
- B1.92 10⁻¹⁷ ~N
- C0.192 N
- DNone of these
Correct answer
B. 1.92 10⁻¹⁷ ~N
Step-by-step solution
Given, electric field, E_y=600 V m (t- x c ) ...(i) We know that, E=E₀ (t- x c ) .....(ii) On comparing Eqs. (i) and (ii), we get E₀=600 ~V / m and C=3 10^8 ~m / s Maximum magnetic field, aligned & B₀= E₀ C & B₀= 600 3 10^8 =2 10⁻⁶ ~T aligned aligned F_m & =q v B₀=2 ev B₀ & =2 1.6 10⁻¹⁹ 3 10^8 2 10⁻⁶ & =19.2 10⁻¹⁷ ~N aligned