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JIPMER 2013
Exam
JIPMER
Year
2013
Subject
Physics
Chapter
Laws of Motion

JIPMER 2013 · Physics · Laws of Motion

A car of mass 1000 kg moves on a circular track of radius 40 m. If...

A car of mass 1000 kg moves on a circular track of radius 40 m. If the coefficient of friction is 1.28. The maximum velocity with which the car can be moved, is

Options

  1. A22.4 m/s22.4 \mathrm{~m} / \mathrm{s}
  2. B112 m/s112 \mathrm{~m} / \mathrm{s}
  3. C0.64×401000×100 m/s\frac{0.64 \times 40}{1000 \times 100} \mathrm{~m} / \mathrm{s}
  4. D1000 m/s1000 \mathrm{~m} / \mathrm{s}

Correct answer

A. 22.4 m/s22.4 \mathrm{~m} / \mathrm{s}

Step-by-step solution

 The maximum velocity vmax⁡=μrg=1.28×40×9.8=22.4m/s\begin{aligned} & \text{ The maximum velocity } v_{\max }=\sqrt{\mu r g} \\ & =\sqrt{1.28 \times 40 \times 9.8} \\ & =22.4 \mathrm{ m} / \mathrm{s} \\ & \end{aligned}
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