The engine of a jet aircraft applies a thrown force of 10^5 ~N during take off and causes the plane to attain a velocity of 1 ~km / s in 10 s . The mass of the plane is

Correct answer: B. 10^3 ~kg Acceleration produced in jet = Change in velocity Time a=((10^3-0))/(10) Mass = Force Acceleration =(10^5)/(10^2) =10^3 kg

JIPMER 2012

Exam: JIPMER
Year: 2012
Subject: Physics
Chapter: Laws of Motion

JIPMER 2012 · Physics · Laws of Motion

The engine of a jet aircraft applies a thrown force of 10^5 ~N...

The engine of a jet aircraft applies a thrown force of

10^5 \mathrm{~N}

during take off and causes the plane to attain a velocity of

1 \mathrm{~km} / \mathrm{s}

in 10 s . The mass of the plane is

Options

A $10^2 \mathrm{~kg}$
B $10^3 \mathrm{~kg}$
C $10^4 \mathrm{~kg}$
D $10^5 \mathrm{~kg}$

Correct answer

B. $10^3 \mathrm{~kg}$

Step-by-step solution

Acceleration produced in jet

=\frac{\text{ Change in velocity }}{\text{ Time }} a=\frac{\left(10^3-0\right)}{10} \therefore

Mass

=\frac{\text{ Force }}{\text{ Acceleration }}=\frac{10^5}{10^2} =10^3

\mathrm{ kg}

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