A bullet of mass 20 g and moving with 600 ~m / s collides with a block of mass 4 kg hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision?

Step-by-step solution

According to conservation of linear momentum, m₁ v₁=m₁ v+m₂ v₂ where v₁ is velocity of bullet before collision, v is velocity of bullet after the collision and v₂ is the velocity of block. 0.02 600=0.02 v+4 v₂ Here, v₂= 2 gh = 2 10 0.2 =2 ~m / s 0.02 600=0.02 v+4 2 0.02 v=12-8 v= 4 0.02 =200 ~m / s