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JIPMER2009PhysicsLaws of Motion

Diwali rocket is ejecting 50 g of gases / s at a velocity of 400 ~m / s . The accelerating force on the rocket will be

Options

  1. A22 dyne
  2. B20 N
  3. C20 dyne
  4. D100 N

Correct answer

B. 20 N

Step-by-step solution

The accelerating force on the rocket = upward thrust = m t u Given, m t =50 10⁻³ ~kg / s , v=400 ~m / s So, accelerating force =50 10⁻³ 400=20 ~N

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