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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Physics
Chapter
Laws of Motion

JIPMER 2015 · Physics · Laws of Motion

A monkey of mass 15 kg is climbing on a rope with one end fixed to...

A monkey of mass 15 kg is climbing on a rope with one end fixed to the ceiling. If it wishes to go up with an acceleration 1 m/s21 \mathrm{~m} / \mathrm{s}^2, how much force should it apply to the rope if rope is 5 m long and the monkey starts from rest?

Options

  1. A150 N
  2. B>160 N\gt160 \mathrm{~N}
  3. C165 N
  4. D150<T≤160 N150 \lt T \leq 160 \mathrm{~N}

Correct answer

C. 165 N

Step-by-step solution

The mass of monkey =15 kga=1 m/s2=15 \mathrm{~kg} a=1 \mathrm{~m} / \mathrm{s}^2 For the motion of the monkey T−[15g−15(1)]=0T-[15 g-15(1)]=0 Hence, TT is tension in the string T=15g+15T=15 g+15T=15(10+1)=15×11=165 N\begin{aligned} T & =15(10+1)=15 \times 11 \\ & =165 \mathrm{~N}\end{aligned}$$
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