An ideal solenoid having 5000 turns / m has an aluminium core and carries a current of 5 A . If _ Al =2.3 10⁻⁵ , then the magnetic field developed at centre will be

Step-by-step solution

Given, n=5000 turns / m , i=5 ~A , _ Al =2.3 10⁻⁵ , B= ? As, B= ₀(H+I) where, aligned H & = B₀ ₀ = ₀ n i ₀ =n i & =5000 5=2.5 10^4 ~A / m aligned aligned & and I= H=2.3 10⁻⁵ 2.5 10^4 & =0.575 ~A / m & B= ₀(H+l) & =4 10⁻⁷ (2.5 10^4+0.575 ) T & =0.031 ~T & aligned