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JIPMER 2004
Exam
JIPMER
Year
2004
Subject
Physics
Chapter
Motion in Two Dimensions

JIPMER 2004 · Physics · Motion in Two Dimensions

A stone is thrown with an initial speed of 4.9 ~m / s from a bridge...

A stone is thrown with an initial speed of 4.9 m/s4.9 \mathrm{~m} / \mathrm{s} from a bridge in vertically upward direction. It falls down in water after 2 sec . The height of bridge is

Options

  1. A24.7 m
  2. B19.8 m
  3. C9.8 m
  4. D4.9 m

Correct answer

C. 9.8 m

Step-by-step solution

Here: Initial velocity u=−4.9 m/su=-4.9 \mathrm{~m} / \mathrm{s} (- ve is due to vertically upward motion) Total time t=2sect=2 \mathrm{sec} The height of the bridge is given by s=ut+12gt2s=u t+\frac{1}{2} g t^2=−4.9×2+12×9.8×(2)2=−9.8+19.6=9.8 m\begin{aligned} & =-4.9 \times 2+\frac{1}{2} \times 9.8 \times(2)^2 \\ & =-9.8+19.6=9.8 \mathrm{~m}\end{aligned}$$
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