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JIPMER 2012
Exam
JIPMER
Year
2012
Subject
Physics
Chapter
Wave Optics

JIPMER 2012 · Physics · Wave Optics

In Young's double slit experiment with sodium vapour lamp of...

In Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

Options

  1. Asin⁡−1(0.01)\sin ^{-1}(0.01)
  2. Bsin⁡−1(0.0001)\sin ^{-1}(0.0001)
  3. Csin⁡−1(0.001)\sin ^{-1}(0.001)
  4. Dsin⁡−1(0.1)\sin ^{-1}(0.1)

Correct answer

C. sin⁡−1(0.001)\sin ^{-1}(0.001)

Step-by-step solution

In Young's double slit experiment half angular width is given by sin⁡θ=λd\sin \theta=\frac{\lambda}{d} =589×10−90.589×10−3=10−3=\frac{589 \times 10^{-9}}{0.589 \times 10^{-3}}=10^{-3} ⇒θ=sin⁡−1(0.001)\Rightarrow \quad \theta=\sin ^{-1}(0.001)
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