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JIPMER 2011
Exam
JIPMER
Year
2011
Subject
Zoology
Chapter
Principles of Inheritance and Variation

JIPMER 2011 · Zoology · Principles of Inheritance and Variation

A woman with two genes (one on each X -chromosome) for haemophilia...

A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the X-chromosome marries a normal man. How will the progeny be?A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the

Options

  1. AAll sons and daughters are haemophilic and colourblind
  2. BHaemophilic and colourblind daughters
  3. C50%50 \% haemophilic colourblind sons and 50%50 \% haemophilic sons
  4. D50%50 \% haemophilic daughters and 50%50 \% colourblind daughters

Correct answer

C. 50%50 \% haemophilic colourblind sons and 50%50 \% haemophilic sons

Step-by-step solution

Haemophilia and colour blindness both are recessive X-linked traits. They express in males when present in single copy (heterozygous) but in females, they express only when present in homozygous condition. A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the Results (a) 50%50 \% sons are colourblind and haemophilic. (b) 50%50 \% sons are haemophilic only. (c) 50%50 \% daughters are carrier for colour blindness and haemophilia. (d) 50%50 \% daughters are carrier for haemophilia only.
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