( 25 ~cm ³ ) of oxalic acid completely neutralized ( 0.064 ~g ) of sodium hydroxide. Molarity of the oxalic acid solution is

Step-by-step solution

Given, V (oxalic acid) =25 ~cm ³W(N a O H)=0.064 gM (oxalic acid) =? Since, moles of oxalic acid = mole of N a O HV (oxalic acid) N (oxalic acid) = w M (N a O H) N ( oxalic acid) = 0.064 1000 25 40 =0.064 Normality = Molarity Basicity Molarity = 0.064 2 =0.32 Note: Basicity of oxalic acid is 2