If ( 3.01 10²⁰ ) molecules are removed from ( 98 mg ) of ( H ₂ SO ₄ ), then number of moles of ( H ₂ SO ₄ ) left are

Step-by-step solution

1 mole of H ₂ SO ₄=6.022 10²³ molecules of H ₂ SO ₄=98 ~g of H ₂ SO ₄98 mg =1 10⁻³ moles =6.022 10²⁰ molecules of H ₂ SO ₄ No. of molecules removed =3.01 10²⁰ No. of molecules left =6.023 10²⁰-3.01 10²⁰=6.023 10²⁰-3.01 10²⁰=3.01 10²⁰ molecules left 6.022 10²³ molecules of H ₂ SO ₄=1 mole 1 molecule = 1 6.022 10²³ moles 3.01 10²⁰ molecules = 3.01 10²⁰ 6.023 10²⁰ =0.5 10⁻³ mol