KCET2014ChemistryGeneral Organic Chemistry
A correct statement is
Options
- A( [ array lll ZnBr ₆ & ]³⁻ & is tetrahedral. array . )
- B( [N i (N H₃ )₆ ]²⁺ ) is an inner orbital complex
- C( [ Co ( NH ₃ )₆ ]²⁺ ) is paramagnetic.
- D( [ CoBr ₂(e n)₂ ]⁻ )exhibits linkage isomerism.
Correct answer
C. ( [ Co ( NH ₃ )₆ ]²⁺ ) is paramagnetic.
Step-by-step solution
Option (1) [ MnBr ₄ ]²⁻ Br ⁻ weak ligand does not allow pairing of e⁻ s , therefore, hybridization of the Mn in complex is sp3 and geometry is tetrahedral. Option (2) [ Ni ( NH ₃ )₆ ]²⁺ NH ₃ is a strong field ligand, therefore, pairing of electrons will take place. But due to insufficiency of vacant orbital, pairing will not take place Electronic configuration of Ni ( Z =8)[ Ar ] 3 d⁸ 4 s² Electronic configuration of N i²⁺ is [ Ar ] 3 d⁸N i²⁺ in the presence of strong field ligand array |l|l|l|l|l| 1 L & 1 L & 1 L