If an aqueous solution of NaF is electrolysed between inert electrodes, the product obtained at anode is

Step-by-step solution

Aqueous NaF, when electrolysed between inert electrodes we always get O ₂ at anode, as: At cathode 2 H ⁺+2 e⁻ H ₂ At anode 4 OH ⁻ 2 H ₂ O + O ₂+4 e⁻ Also, if any fluorine is liberated, that too reacts with H ₂ O . 2 ~F ₂+2 H ₂ O 4 HF + O ₂ So, ultimate product is oxygen.