KCET2012ChemistryRedox Reactions
The volume of 0.1 M oxalic acid that can be completely oxidized by 20 ~mL of 0.025 M KMnO ₄ solution is
Options
- A25 ~mL
- B12.5 ~mL
- C37.5 ~mL
- D125 ~mL
Correct answer
B. 12.5 ~mL
Step-by-step solution
N = molecular weight equivalent weight M aligned N _ KMnO ₄ &= 158 31.6 0.025 &=0.125 ~N _ O . A &= 126 63 0.1=0.2 N _ V V ₁ &= N ₂ ~V ₂ 0.2 V &=0.125 20 & 0.125 20 ~V &=0.2 &=12.5 ~mL aligned