50 ~cm ³ of 0.2 ~N HCl is titrated against 0.1 ~N NaOH solution. The titration was discontinued after adding 50 ~cm ³ of NaOH . The remaining titration is completed by adding 0.5 ~N KOH . The volume of KOH required for completing the titrat

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50 ~cm ³ of 0.2 ~N HCl is titrated against 0.1 ~N NaOH solution. The titration was discontinued after adding 50 ~cm ³ of NaOH . The remaining titration is completed by adding 0.5 ~N KOH . The volume of KOH required for completing the titration is

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Correct answer: B. 10 ~cm ³

No. of equivalent of HCl remaining after adding aligned 50 ~cm ³ of 0.1 ~N NaOH &= 0.2 50-0.1 50 100 &= 0.5 100 aligned Volume of 0.5 ~N KOH required 0.5 100 eq aligned & V 0.5 1000 V &= 0.5 100 1000 0.5 &=10 ~cm ³ aligned

50 ~cm ³ of 0.2 ~N HCl is titrated against 0.1 ~N NaOH solution. The titration was discontinued after adding 50 ~cm ³ of NaOH . The remaining titration is completed by adding 0.5 ~N KOH . The volume of KOH required for completing the titration is

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