( 1 ) mole of ( NaCl ) is doped with ( 10⁻⁵ ) mole of ( SrCl ₂ . ) The number of cationic vacancies in the crystal lattice will be:

Step-by-step solution

(C) ( 1 ~mol SrCl ₂ ) gives ( 1 ) cationic vacancy. ( 10⁻⁵ ) moles of ( SrCl ₂ ) gives ( 10⁻⁵ ) mole cationic vacancies. ( ) The number of cationic vacancy in ( 1 ) moles of ( NaCl ) when it is doped with ( 10⁻⁵ ) moles of ( SrCl ₂ ) is ( 6.022 10¹⁸ )