KCET2026ChemistryThermodynamics (C)
A gas can be taken from A to B via two different paths ACB and ADB. When path ACB is used, 60 J of heat flows into the system and 30 J of work is done by the system. If path ADB is used, work done by the system is 10 J. The heat flow into the system in path ADB is
Options
- A80 J
- B20 J
- C100 J
- D40 J
Correct answer
D. 40 J
Step-by-step solution
According to the first law of thermodynamics, the change in internal energy is given by: U = Q - W where Q is the heat added to the system and W is the work done by the system. For path ACB: Heat added, Q_ ACB = 60 J Work done, W_ ACB = 30 J U = 60 - 30 = 30 J Since internal energy is a state function, the change in internal energy U between states A and B is the same for any path. Therefore, for path ADB, U = 30 J. For path ADB: Work done, W_ ADB = 10 J Using the first law of thermodynamics again: U = Q_ ADB - W_