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KCET2010ChemistryThermodynamics (C)

The amount of heat evolved when 500 ~cm ³ of 0.1 M HCI is mixed with 200 ~cm ³ of 0.2 M NaOH is

Options

  1. A2.292 ~kJ
  2. B1.292 ~kJ
  3. C0.292 ~kJ
  4. D3.392 ~kJ

Correct answer

A. 2.292 ~kJ

Step-by-step solution

HCl + NaOH NaCl + H ₂ O Initial moles array lcll 500 0.1 1000 & 200 0.2 1000 & 0 & 0 array =0.05=0.04 array llll Final moles & & 0.05-0.04 & 0 & 0.04 & 0.04 array In neutralisation of 1 mole of NaOH by 1 mole HCl , heat evolved =57.3 ~kJ To neutralise 0.04 mole of NaOH by 0.04 mole of HCl , heat evolved will be =57.3 0.04 ~kJ =2.292 ~kJ

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