Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET202523 May 2025Evening ShiftChemistryRedox ReactionsActual

H ₂ O ₂ reduces KMnO ₄ in acidic medium to ' x ' and in basic medium to ' y '. What are x and y ?

Options

  1. Ax= MnO ₂, y= Mn ²⁺
  2. Bx= Mn ²⁺, y= MnO ₂
  3. Cx= MnO ₄²⁻, y= Mn ²⁺
  4. Dx= MnO ₂, y= MnO ₄²⁻

Correct answer

B. x= Mn ²⁺, y= MnO ₂

Step-by-step solution

NO SOLUTION

Practice Redox Reactions on Quantrex Academy →

More from Redox Reactions

x moles of K₂ Cr₂ O₇ oxidises 1 mole of ferrous oxalate, in acidic medium. Hence 'x' is: 2026In the redox reaction, taking place in acidic medium: X MnO ₄^- (aq) + Y SO ₂(g) Mn ⁺²(aq) + HSO ₄^- (aq) , the ratio of X:Y in a stoichiometrically balanced equation will be 2026In the reaction, Cr ₂ O ₇²⁻ + 4 H ₂ O ₂ + 2 H ^+ 2 CrO ₅ + H ₂ O The change in oxidation state of Cr is: 2026What are the numbers of protons ( H ^+ ) and electrons ( e ^- ), respectively, required for the reduction of [ Cr ₂ O ₇]²⁻ to Cr ³⁺ under an aqueous acidic condition? 2026Given below are two statements. Statement-I: In H ₂ O ₂ , each oxygen atom is assigned an oxidation number of -1 , in RbO ₂ each oxygen atom is assigned an oxidation number of - 1 2026a C ₂ O ₄²⁻ + b MnO ₄^- + c H ^+ x Mn ²⁺ + y H ₂ O + z CO ₂ a and x respectively are 2026What is the number of electrons gained by Cl atom when n mole of ClO ₄^- is transformed into n mole of ClO ₂^- ion? 2026What is the oxidation number of Cl in HOClO ₂ ? 2026 Full Redox Reactions list All AP EAMCET PYQs