KCET2017MathematicsDeterminants
The value of ( _ 0 1- 4 1- 6 ) is
Options
- A( 4 9 )
- B( 9 4 )
- C( 9 3 )
- D( 3 4 )
Correct answer
A. ( 4 9 )
Step-by-step solution
Given that, ( _ 0 1- 4 1- 6 ) It is a ( 0 0 ) form. Now using L' Hospital rule we get ( _ 0 4 4 6 6 ) It is a ( 0 0 ) form. Now using L' Hospital rule we get ( _ 0 (4)²( 4 ) (6)²( 6 ) = 4 4 6 6 = 4 9 )