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KCET2015MathematicsDeterminants

A box contains ( 6 ) red marbles numbers from ( 1 ) through ( 6 ) and ( 4 ) white marbles ( 12 ) through ( 15 . ) Find the probability that a marble drawn 'at random' is white and odd numbered.

Options

  1. A( 1 7 )
  2. B( 1 5 )
  3. C( 1 9 )
  4. D( 1 6 )

Correct answer

B. ( 1 5 )

Step-by-step solution

Number of red marbles are 6(1 to 6 ) , number of white marbles are 4(12 to 15 ) . So, R1, R2, R3, R4, R5, R6, W12, W13, W14, W15 Total number of marbles are 10. We have, white + odd = W13, W15 So, required probability is 2 10 = 1 5

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