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KCET2014MathematicsDeterminants

Equation of the plane perpendicular to the line ( x 1 = y 2 = z 3 ) and passing through the point ( (2, ), ( 3,4) ) is

Options

  1. A( x+2 y+3 z=9 )
  2. B( x+2 y+3 z=20 )
  3. C( 2 x+3 y+z=17 )
  4. D( 3 x+2 y+z=16 )

Correct answer

B. ( x+2 y+3 z=20 )

Step-by-step solution

Given that, x 1 = y 2 = z 3 (1) And point is P (2,3,4) . Now, direction ratio's of normal to the plane is 1,2,3 . So, equation is 1 x+2 y+3 z+d=0 It passes through point P (2,3,4) So, 2+6+12+d=0 d=-20 Therefore, required equation is x+2 y+3 z=20

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